4000 + 2000 = 0 ... ? ? ?

intresting but...!!!!!!!!!!!!!!!!!!!!!!!!!1111

This can actually be proven wrong...but anything can = anything...nubs

Quote:

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Originally Posted by elberbawy1

let a = 4000,

b = 2000 and

c = 6000

a + b = c

Multiply both sides by a + b

(a + b) (a + b ) = c (a + b)

a*a + ab + ba + b*b = ca + cb

a*a + ab - ca = cb - b*b - ba

a( a + b -c) = -b(b + a - c)

so a = - b

a + b = 0

Hence 4000 + 2000 = 0.

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Ok, where is the mistake. I mean, where is the wrong step. This can't be.

this is lame....
not funny makes me cry!!!

it's not funny, maybe next time

if a=4000;b=2000 & c=6000;
you can't cancel out (a+b-c) from both side of the equation. bcoz (a+b-c)=0.
a( a + b -c) = -b(b + a - c) ,
You r doing wrong in this line, This is beyond the low of mathematics, If you will do so a*0 = -b*0, cancel out 0 from both side you will get a=-b, This is not possible boss?

Haha, that was a funny one

I remember my math teacher doing something like this back in high school. It was entertaining to say the least.

very interesting jokes.

Not lend money to mathematician

Its an interesting maths problem