Day 2 - Variables - Become PHP Expert in 30 days

DAY 2 PROGRAMMING. EXAMPLE 5

http://php.flashwebhost.com/vineesh/...ariables_5.php

MY CODE IS:

Code:

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<?php


$numberOfWorkers = 5;
$wagePerWorker = 650;


echo '<p>' . 'Total Number of workers ' . '= ' . $numberOfWorkers . '</p>';


echo '<p>' . 'Wage per worker ' . '= '. $wagePerWorker . '</p>';


echo '<p>' . 'Total wage for all workers will be ' . '= ' . ($numberOfWorkers * $wagePerWorker) . '/-' . "</p>";

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Quote:

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Originally Posted by vineesh

http://php.flashwebhost.com/vineesh/...ariables_2.php

I was facing difficulty to insert a full stop after a sentence. But I managed to make it work. My code is

Code:

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<?php

$staffName = 'Ramesh';
$companyName = 'HOSTONNET';

$staffName2 = 'Suresh';

$staffName3 = 'Tom';

echo $staffName . ' is working in ' . $companyName;  echo '.'; echo ' But '; echo $staffName2; echo ' not.' ;

echo '<br>';

echo $staffName3 . ' also working in ' . $companyName . 'for the past 10 years'; echo '.';

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Is there any issue with this ?

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your code is working and error free. I also got a suggestion that it could be reduced too.
i have modified your code in here:

Code:

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<?php


$staffName = 'Ramesh';
$companyName = 'HOSTONNET';


$staffName2 = 'Suresh';


$staffName3 = 'Tom';


echo $staffName . ' is working in ' . $companyName.'. But '.$staffName2.' is not.<br>'.$staffName3.' also working in '.$companyName .' for the past 10 years.';

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you could do everything in one echo. lesser code faster work ;)

PHP Code:

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<?php

$name= 'crazyfrog';
$action = ' is coming to town.';
$n1 = 8;
$n2=9;

echo $name.$action;
echo '<br>';
echo '8 + 9 = ' . ($n1+$n2);
echo '<br>' . (8*9);

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1 doubt

does php use any preference rules from maths?
like BODMAS (Bracket, of, division, multiplication, addition, subtraction) rule or something?
when echoed does the compiler compiles the things in bracket first?

i had an error when i omitted the bracket of 8*9

PHP Code:

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echo '<br>'.(8*9); 


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had error with this code.

PHP Code:

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echo '<br>'.8*9; 


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@Austinwhite Please don't ask too much complicated maths questions. No one here understand BODMAS or preference rules from maths :confused:

PHP Code:

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echo '<br>'.8*9; 


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I think PHP is confused about that to do here. So it is better use brackets when you use maths operation.

Quote:

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Originally Posted by annie

I got an error while adding break in http://php.flashwebhost.com/annie/company.php

Code:

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Parse error:  syntax error, unexpected '>' in /home/fwhphp/public_html/annie/company.php on line 3

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Code:

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<?php
$companyname = 'Relience';
echo $companyname <br> ;
$companyname = 'Whirpool';
echo $companyname ;

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Doubt 1
Is it possible to use same variable name for multiple values ?

Doubt 2
Is variable name is case sensitive ?

I mean both the following variables will give different values in the same script ?

Quote:

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$variableName
$variablename

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Quote:

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Originally Posted by melbin

Doubt 1
Is it possible to use same variable name for multiple values ?

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Variables can store only 1 value at a time. If you store new value to a variable, value of variable changes to that new value.

Quote:

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Originally Posted by melbin

Doubt 2
Is variable name is case sensitive ?

I mean both the following variables will give different values in the same script ?

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Variables are case sensitive.

DAY 2 PHP PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_6.php

Code:

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<?php


$computerPrice = '20000' ;
$printerPrice = '5000' ;
$discount = 0.1; // 10% discount.


echo ' Total cost = Rs: ' . ($computerPrice+$printerPrice) . ' /- ' ;
echo '<br>' ;
echo ' Price after discount = Rs: ' . ( ($computerPrice + $printerPrice) -  (($computerPrice + $printerPrice) *  $discount)) . '/-' ;

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DAY 2 PHP PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_7.php

Code:

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<?php


$computerPrice = 20000 ;
$printerPrice = 5000 ;
$discount = 0.2 ; // 20% discount.
$totalCost = $computerPrice + $printerPrice ;


echo ' Total cost = Rs: ' . $totalCost . '/-' ;


echo '<br>' ;


echo ' Price after discount = Rs. ' . ($totalCost - ($totalCost * $discount )) . '/-' ;

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I just tried with $discount = 0.1 , $discount = 0.2.

But when i add $discount = 12 , the result was wrong.

So i searched in google for "percentage formula in php" and i got the following

PHP Code:

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<?php$shirt_price = 300;$pant_price = 300;$discount = 12;$total_cost = ($shirt_price+$pant_price);
echo 'Total price is Rs :  ' . $total_cost . '/-';
echo '<br>';
echo ' Price after discount is Rs : ' . ($total_cost - ($total_cost*$discount / 100)). '/-';

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See the result at http://php.flashwebhost.com/sibichan...ariables_7.php

DAY 2 PROGRAMMING:

http://php.flashwebhost.com/vineesh/...ariables_6.php

Seems it worked :). My code is:

Code:

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<?php


$costOfApple = 50;
$costOfOrange = 30;
$discount = 0.5; // 50% discount.


echo 'Cost of an apple = ' . $costOfApple . '<br>' . 'Cost of Orange = ' . $costOfOrange . '<br>';
echo 'Cost of apple + Orange = ' . ($costOfApple + $costOfOrange) . '<br>';
echo 'Discount ' . $discount . '<br>' ;
echo 'Cost after discount = ' . ( ($costOfApple + $costOfOrange) - (($costOfApple + $costOfOrange) * $discount ) ) . '/-';

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