Which puzzle do I solve?
Which puzzle do I solve?
if we assume there is a 50-50% chance of having a girl or a boy then:
so what is the chance that you have a girl first?
50%, what is the chance you have a girl again? 50% and so on
so:
1 boy 50% chance
1 boy + 1 girl 25% chance
1 boy + 2 girl 12.5% chance
1 boy + 3 girl 6.25% chance
etc
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Number of boys is:
SUM as n goes from 1 to infinity of (0.5^n)
Number of girls is:
SUM as n goes from 1 to infinity of ((n-1)*0.5^(n+1))
so the ratio is the ratio of those two values.
cool stuff
All those formulas are nice but this is a what came first the chicken or the egg. However many families you start with is all the families you have as their is a boy there already so no other children would be born.
that sound is good
Originally Posted by http://neerajsingh.bizhat
Well the ages of the daughters are 8 years, 3 years and 3 years
My approach:
1- First factor 72 in three parts.
2- Now we need to consider that one where the sum is something that is on the building.
3- As the second mathmatician got confused, that means there are two factors whose sum equal the same. They are 8*3*3 and 2*6*6. Both equal to 14.
4- Now he needed one more hint to chose one of them. So when the first mathmatician about her Eldest daughter, that means it can be only 8*3*3, because in other case, there is a draw.
Hnce the answer. Thanks for posting the puzzle dear, what a nice way to start your posting in a forum.
Wish you a very wonderful time here among us Bizhatians.
nice dude 123123
ok its cool
nice and very good
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