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Thread: Day 2 - Variables - Become PHP Expert in 30 days

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  1. #1
    Join Date
    Sep 2003
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    Post example links, experiment (best way to learn) and discuss. No cut and paste please. Type the examples yourself, make mistake, try to fix it yourself, , think, refer back, post you code, so others can fix it for you. Lean from your mistakes (or others).
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  2. #2
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    Nov 2009
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    76,596

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    http://php.flashwebhost.com/sherly/add.php

    Code:
    <?php
    
    $M = 20;
    $N = 50;
    echo $M + $N;

  3. #3
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    Sep 2003
    Posts
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    Quote Originally Posted by sherlyk View Post
    http://php.flashwebhost.com/sherly/add.php

    Code:
    <?php
    
    $M = 20;
    $N = 50;
    echo $M + $N;
    Quote Originally Posted by admin View Post
    It is always better to use descriptive name for variables, so you what what is stored in a variable. For example, to store mark, we use variable $mark
    It is ok, but better use descriptive names for variables. One letter variable names can be confusing in most cases.
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  4. #4
    Join Date
    Sep 2003
    Location
    india
    Posts
    11,527

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    I got an error while adding break in http://php.flashwebhost.com/annie/company.php

    Code:
    Parse error:  syntax error, unexpected '>' in /home/fwhphp/public_html/annie/company.php on line 3 
    Code:
     <?php
    $companyname = 'Relience';
    echo $companyname <br> ; 
    $companyname = 'Whirpool'; 
    echo $companyname ;

  5. #5
    Join Date
    Nov 2009
    Posts
    76,596

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    I got an error http://php.flashwebhost.com/sherly/name.php

    Code:
    Parse error:  syntax error, unexpected '' ;' (T_ENCAPSED_AND_WHITESPACE), expecting ',' or ';' in /home/fwhphp/public_html/sherly/name.php on line 7
    Code:
    <?php
    $my_string = 'Hi Meera. My anme is Neena';
    $my_number = 8;
    $my_letter = N;
    echo $my_string;
    echo $my_number;
    echo $my_letter' ;
    Last edited by sherlyk; 05-09-2014 at 07:08 AM.

  6. #6
    Join Date
    Sep 2003
    Posts
    3,040

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    Quote Originally Posted by sherlyk View Post
    I got an error http://php.flashwebhost.com/sherly/name.php

    Code:
    <?php
    $my_string = 'Hi Meera. My anme is Neena';
    $my_number = 8;
    $my_letter = N;
    echo $my_string;
    echo $my_number;
    echo $my_letter' ;
    Good, more friendly code with some string.

    Code:
    <?php
    
    $my_string = 'Hi Meera. My anme is Neena';
    $my_number = 8;
    $my_letter = N;
    
    echo '<h1>About Me</h1>';
    echo $my_string;
    echo '<br>';
    echo 'My number is ' . $my_number;
    echo '<br>';
    echo 'My Name start with ' . $my_letter' ;
    echo '<br>';
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  7. #7
    Join Date
    Sep 2003
    Posts
    3,040

    Default

    Quote Originally Posted by annie View Post
    I got an error while adding break in http://php.flashwebhost.com/annie/company.php

    Code:
    Parse error:  syntax error, unexpected '>' in /home/fwhphp/public_html/annie/company.php on line 3 
    Code:
     <?php
    $companyname = 'Relience';
    echo $companyname <br> ; 
    $companyname = 'Whirpool'; 
    echo $companyname ;
    Problem is on line number 3.

    Code:
    echo $companyname <br> ;
    To fix, replace that line with

    Code:
    echo $companyname .  '<br>' ;
    $companyname is a variable. We use DOT to join it with string <br>. String should start with a quote, end with a quote.

    As for variable name, proper naming convention is $companyName, because it is two words, and easy to read.


    Fixed code

    Code:
    <?php
    
    $companyName = 'Relience';
    
    echo $companyname .  '<br>'; 
    
    // here we store another text to same variable $companyName
    $companyName = 'Whirpool'; 
    
    echo $companyname ;
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  8. #8
    Join Date
    Sep 2003
    Location
    india
    Posts
    11,527

    Default

    http://php.flashwebhost.com/annie/day_2_variables_3.php

    Code:
     
    <?php
    $name = 'George';
    $Rank = 1;
    $Mark = 800;
    $School = 'Raja Giri Public School';
    echo $name . ' from ' . $School . ' got Rank ' . $Rank . ' He have ' . $Mark . 'Marks';

  9. #9
    Join Date
    Nov 2009
    Posts
    76,596

    Default

    I didn't get the correct answer. http://php.flashwebhost.com/sherly/variable.php

    Code:
    <?php
    
    $variable12 = $variable7 + $variable5;
    echo $variable7;
    echo " + ";
    echo $variable5;
    echo " = ";
    echo $variable12;

  10. #10
    Join Date
    Nov 2009
    Posts
    76,596

    Default

    http://php.flashwebhost.com/sherly/age.php

    Code:
    <?php
    
    $name = 'Joseph';
    $yearBorn = 1975;
    $currentYear = 2014;
    $age = $currentYear - $yearBorn;
    
    print ("$name is $age years old. ")

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