# Thread: 4000 + 2000 = 0 ... ? ? ?

1. Junior Member BizHat Newbie
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Oct 2006
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intresting but...!!!!!!!!!!!!!!!!!!!!!!!!!1111

2. Junior Member BizHat Newbie
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Oct 2006
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This can actually be proven wrong...but anything can = anything...nubs

3. Junior Member BizHat Newbie
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## Re: 4000 + 2000 = 0 ... ? ? ?

Originally Posted by elberbawy1
let a = 4000,

b = 2000 and

c = 6000

a + b = c

Multiply both sides by a + b

(a + b) (a + b ) = c (a + b)

a*a + ab + ba + b*b = ca + cb

a*a + ab - ca = cb - b*b - ba

a( a + b -c) = -b(b + a - c)

so a = - b

a + b = 0

Hence 4000 + 2000 = 0.
Ok, where is the mistake. I mean, where is the wrong step. This can't be.

4. Junior Member BizHat Newbie
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## Re: 4000 + 2000 = 0 ... ? ? ?

this is lame....
not funny makes me cry!!!

5. Junior Member BizHat Newbie
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Dec 2006
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it's not funny, maybe next time

6. Junior Member BizHat Newbie
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Mar 2005
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## wrong

if a=4000;b=2000 & c=6000;
you can't cancel out (a+b-c) from both side of the equation. bcoz (a+b-c)=0.
a( a + b -c) = -b(b + a - c) ,
You r doing wrong in this line, This is beyond the low of mathematics, If you will do so a*0 = -b*0, cancel out 0 from both side you will get a=-b, This is not possible boss?

7. Junior Member BizHat Newbie
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Jan 2007
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Haha, that was a funny one

8. Junior Member BizHat Newbie
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Feb 2007
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I remember my math teacher doing something like this back in high school. It was entertaining to say the least.

9. very interesting jokes.

Not lend money to mathematician

10. Junior Member BizHat Newbie
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Feb 2007
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Its an interesting maths problem

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