Day 2 - Variables - Become PHP Expert in 30 days

[sherlyk]

http://php.flashwebhost.com/sherly/age.php

<?php

$name = 'Joseph';
$yearBorn = 1975;
$currentYear = 2014;
$age = $currentYear - $yearBorn;

print ("$name is $age years old. ")

[admin]

http://php.flashwebhost.com/sherly/age.php

<?php

$name = 'Joseph';
$yearBorn = 1975;
$currentYear = 2014;
$age = $currentYear - $yearBorn;

print ("$name is $age years old. ")

Semicolon at end of print statement missing.

print function same as echo, but use echo, forget print. echo is more popular, also there are more ways to print, some complicated, but is not required for most programming project.

print ("$name is $age years old. ")

Proper usage

echo $name . ' is ' .  $age . ' years old. ';

Or

echo "$name  is  $age years old. ";

Advantage of using single quote is PHP know it is just string, so it will be faster. If using double quote, PHP compilter need to look for variable inside the string and convert it to its value, that need more processing time (not much, still do that way as a convention whenever possible).

[vineesh]

http://php.flashwebhost.com/vineesh/...ariables_2.php

I was facing difficulty to insert a full stop after a sentence. But I managed to make it work. My code is

<?php

$staffName = 'Ramesh';
$companyName = 'HOSTONNET';

$staffName2 = 'Suresh';

$staffName3 = 'Tom';

echo $staffName . ' is working in ' . $companyName;  echo '.'; echo ' But '; echo $staffName2; echo ' not.' ;

echo '<br>';

echo $staffName3 . ' also working in ' . $companyName . 'for the past 10 years'; echo '.';

Is there any issue with this ?

[image]

DAY 2 PHP PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_1.php

<?php


$MovieName = '<b>Mr. Fraud</b>';


echo $MovieName ;

[image]

DAY 2 PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_2.php

<?php


$MovieName = '<b>Mr. Fraud</b>';


echo 'Mohanlal\'s Upcoming Movie '  .  $MovieName;

[image]

DAY 2 PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_3.php

<?php


$MovieName = 'Mr. Fraud' ;
$Starring = 'Mohanlal, Siddique, Dev Gill, Pallavi, Mia, Manjari' ;
$Director = 'B. Unnikrishnan' ;


echo $MovieName . ' is a malayalam movie, ' . $Director . ' is the Director. ' . $Starring . ' in the lead roles. ' ;

[admin]

DAY 2 PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_2.php

<?php


$MovieName = '<b>Mr. Fraud</b>';


echo 'Mohanlal\'s Upcoming Movie '  .  $MovieName;

Variable names always start with smaller case letter.

<?php


$movieName = '<b>Mr. Fraud</b>';


echo 'Mohanlal\'s Upcoming Movie '  .  $movieName;

[image]

DAY 2 PHP PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_4.php

<?php


$numOfBoys = '20' ;
$numOfGirls = '25' ;


echo 'Total number of students = ' . ($numOfBoys+$numOfGirls) ;

[admin]

DAY 2 PHP PROGRAMMING

http://php.flashwebhost.com/tom/day_2_variables_4.php

<?php


$numboys = '20' ;
$numgirls = '25' ;


echo 'Total number of students = ' . ($numboys+numgirls) ;

This program have syntax error on line

echo 'Total number of students = ' . ($numboys+numgirls) ;

$ missing for numgirls.

Proper usage.

<?php

$numBoys = 20;
$numGirls = 25;

echo 'Total number of students = ' . ($numBoys + $numGirls) ;

Only strings values need to be enclosed within quotes (' or ").

Variable names, if two words, Capitalize first letter of 2nd, 3rd, etc.. word.

[admin]

http://php.flashwebhost.com/vineesh/...ariables_2.php

I was facing difficulty to insert a full stop after a sentence. But I managed to make it work. My code is

<?php

$staffName = 'Ramesh';
$companyName = 'HOSTONNET';

$staffName2 = 'Suresh';

$staffName3 = 'Tom';

echo $staffName . ' is working in ' . $companyName;  echo '.'; echo ' But '; echo $staffName2; echo ' not.' ;

echo '<br>';

echo $staffName3 . ' also working in ' . $companyName . 'for the past 10 years'; echo '.';

Is there any issue with this ?

Try this

<?php

$staffName = 'Ramesh';
$companyName = 'HOSTONNET';

$staffName2 = 'Suresh';

$staffName3 = 'Tom';

echo $staffName . ' is working in ' . $companyName .  '.' .  ' But ' .  $staffName2 . ' not.' ;

echo '<br>';

echo $staffName3 . ' also working in ' . $companyName . ' for the past 10 years.';

You can also replace

echo $staffName . ' is working in ' . $companyName .  '.' .  ' But ' . $staffName2 . ' not.' ;

echo '<br>';

echo $staffName3 . ' also working in ' . $companyName . ' for the past 10 years.';

With

echo '<p>' . $staffName . ' is working in ' . $companyName .  '.' .  ' But ' .  $staffName2 . ' not.</p>' ;

echo '<p>' . $staffName3 . ' also working in ' . $companyName . ' for the past 10 years.</p>';